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The value of e2e4 1x ( e (( ex)2+1 )-1e (( ex)2+1 )-1+e ((6- ex)2+1 )-1 )dx is
(1) 1
Put t= x: I= 24 f(t)f(t)+f(6-t)dt, f(t)=e 1t2+1, and a+b=2+4=6
King property (t 6-t): I= 24 f(6-t)f(t)+f(6-t)dt
Add: 2I= 24dt=2 I=1
Answer: (1)
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