Ques. 1JEE Main 2024, 27 January (Evening Shift)
Let e1 be the eccentricity of the hyperbola x216- y29=1 and e2 be the eccentricity of the ellipse x2a2+ y2b2=1, a>b, which passes through the foci of the hyperbola. If e1e2=1, then the length of the chord of the ellipse parallel to the x-axis and passing through (0,2) is :
- 8 53
- 3 5
- 4 5
- 10 53
Answer
(4) 10 53
Solution
Hyperbola: e1= 1+ 916= 54, foci ( 5,0)
e2= 1e1= 45; ellipse through ( 5,0) a=5
b2=a2 (1-e22 )=25 925=9 x225+ y29=1
[figure]
y=2: x225=1- 49= 59 x= 5 53
∴ PQ= 10 53
Answer: (4)