In a uniform magnetic field of 0.049 T, a magnetic needle performs 20 complete oscillations in 5 seconds as shown. The moment of inertia of the needle is 9.8 10-6 kg m2. If the magnitude of magnetic moment of the needle is x 10-5 A m2, then the value of 'x' is : [figure]
- 5 2
- 128 2
- 50 2
- 1280 2
Answer
(4) 1280 2
Solution
Time period: T = 520 = 0.25 s
T = 2 ImB
m = 4 2 IBT2 = 4 2 9.8 10-60.049 (0.25)2
= 4 2 3.2 10-3
= 1280 2 10-5 A m2
x = 1280 2
Answer: (4)