Energy levels A, B and C of a certain atom corresponding to increasing values of energy i.e. EA < EB < EC. If 1, 2 and 3 are wavelengths of radiations corresponding to transitions C to B, B to A and C to A respectively, which of the following relations is correct?
- 3 = 1 + 2
- 3 = 1 2 1 + 2
- 1 + 2 + 3 = 0
- 32 = 12 + 22
Answer
(2) 3 = 1 2 1 + 2
Solution
Energy of emitted photon: E = hc
EC - EA = (EC - EB) + (EB - EA)
hc 3 = hc 1 + hc 2
1 3 = 1 + 2 1 2
3 = 1 2 1 + 2
Answer: (2)