In a moving coil galvanometer, two moving coils M1 and M2 have the following particulars : R1 = 5 , N1 = 15, A1 = 3.6 10-3 m2, B1 = 0.25 T R2 = 7 , N2 = 21, A2 = 1.8 10-3 m2, B2 = 0.50 T Assuming that torsional constant of the springs are same for both coils, what will be the ratio of voltage sensitivity of M1 and M2 ?
- 1 : 1
- 1 : 3
- 1 : 2
- 1 : 4
Answer
(1) 1 : 1
Solution
Voltage sensitivity V = NABkR (k = torsional constant, same for both)
(V.S.)1(V.S.)2 = N1A1B1R1 R2N2A2B2
= 15 3.6 10-3 0.255 721 1.8 10-3 0.50
= 2.7 10-32.7 10-3 = 1
Ratio = 1 : 1
Answer: (1)