Let B1 be the magnitude of magnetic field at center of a circular coil of radius R carrying current I. Let B2 be the magnitude of magnetic field at an axial distance 'x' from the center. For x : R = 3 : 4, B2B1 is :
- 64 : 125
- 25 : 16
- 4 : 5
- 16 : 25
Answer
(1) 64 : 125
Solution
B1 = 0 I2R, B2 = 0 I R22(R2 + x2)3/2
B2B1 = R3(R2 + x2)3/2
x = 3R4 R2 + x2 = 25R216 (R2 + x2)3/2 = 125R364
B2B1 = 64125, i.e. 64 : 125
Answer: (1)