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Determinants · Question 31

JEE Main 2025 (Online) 2nd April Morning ShiftMCQMedium📈 Topic in 42% papers+4−1
1

If the system of linear equations 3x + y + z = 3 2x + y - z = -3 x + 2y + z = 4 has infinitely many solutions, then the value of 22 - 9 is :

  1. 31
  2. 37
  3. 43
  4. 49

Answer

(1) 31

Solution

For infinitely many solutions: = 0 and x = y = z = 0.

= vmatrix 3 & 1 & \ 2 & & -1 \ 1 & 2 & 1 vmatrix = 3( + 2) - 1(2 + 1) + (4 - )

= 3 + 3 + (4 - ) = 0 ...(i)

z = vmatrix 3 & 1 & 3 \ 2 & & -3 \ 1 & 2 & 4 vmatrix = 3(4 + 6) - 1(8 + 3) + 3(4 - )

z = 9 + 19 = 0 = - 199

From (i): - 193 + 3 + (4 + 199 ) = 0

559 = 103 = 611

Check: x = vmatrix 3 & 1 & \ -3 & & -1 \ 4 & 2 & 1 vmatrix = 3 + 5 - (6 + 4 ) = - 43 + 43 = 0 (similarly y = 0), so the system is consistent.

22 - 9 = 12 + 19 = 31

Answer: (1)

JEE Main 2025 (Online) 2nd April Morning Shift

Keep practising — Determinants

2

If the system of equations 2x + y + 3z = 5 3x + 2y - z = 7 4x + 5y + z = 9 has infinitely many solutions, then ( 2 + 2) is equal to :

  1. 30
  2. 26
  3. 22
  4. 18
JEE Main 2025 (Online) 2nd April Evening Shift
3

Let A = [aij] = bmatrix 5 128 & 4 5 \ 5 8 & 4 25 bmatrix. If Aij is the cofactor of aij, Cij = k=12 aikAjk, 1 i, j 2, and C = [Cij], then 8|C| is equal to :

  1. 288
  2. 262
  3. 222
  4. 242
JEE Main 2025 (Online) 29th January Morning Shift
4

Let M and m respectively be the maximum and the minimum values of f(x) = vmatrix 1 + 2 x & 2 x & 4 4x \ 2 x & 1 + 2 x & 4 4x \ 2 x & 2 x & 1 + 4 4x vmatrix, x R Then M4 - m4 is equal to :

  1. 1280
  2. 1040
  3. 1215
  4. 1295
JEE Main 2025 (Online) 29th January Morning Shift

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