Electrolysis of 600 mL aqueous solution of NaCl for 5 min changes the pH of the solution to 12. The current in Amperes used for the given electrolysis is . (Nearest integer).
Answer
2
Solution
At the cathode: 2H2O(l) + 2e- H2(g) + 2OH-(aq)
1 mol of OH- is formed per mole of electrons (1 F).
pH = 12 pOH = 2 [OH-] = 10-2 M (taking the initial NaCl solution as neutral)
nOH- = 10-2 0.600 = 6 10-3 mol
Q = 6 10-3 96500 = 579 C
I = Qt = 5795 60 = 1.93 A 2 A
Answer: 2