A galvanometer having a coil of resistance 30 need 20 mA of current for full-scale deflection. If a maximum current of 3 A is to be measured using this galvanometer, the resistance of the shunt to be added to the galvanometer should be 30X , where X is
- 447
- 298
- 149
- 596
Answer
(3) 149
Solution
Shunt S is in parallel with the galvanometer, so both have the same voltage.
[figure]
IgRg=(I-Ig)S S= 20 302980= 30149
X=149
Answer: (3)