Two long parallel wires X and Y, separated by a distance of 6 cm , carry currents of 5 A and 4A, respectively, in opposite directions as shown in the figure. Magnitude of the resultant magnetic field at point P at a distance of 4 cm from wire Y is x 10-5 T. The value of x is . Take permeability of free space as 0=4 10-7 SI units. [figure]
Answer
1
Solution
[figure]
P is 4 cm from Y and 10 cm from X: BX= 0(5)2 (0.10)=1 10-5 T (into page), BY= 0(4)2 (0.04)=2 10-5 T (out of page)
Opposite directions: B=2 10-5-1 10-5=1 10-5 T
x=1
Answer: 1