Let y=y(x) be the solution of the differential equation 2 x dydx= 2x-4y x, x (0, 2 ). If y ( 3 )=0, then y' ( 4 )+y ( 4 ) is equal to .
Answer
1
Solution
Linear form: dydx+2y x= x, I.F.=e2 x= 2x
y 2x= x x dx= x+C
y ( 3 )=0 0=2+C C=-2
y= x-2 2x, y'=- x+4 x x
y ( 4 )= 1 2-1, y' ( 4 )=2- 1 2
y'+y=1
Answer: 1