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Electromagnetic Induction

JEE Main 2024 (Online) 27th January Morning ShiftMCQEasy📈 Topic in 16% papers+4−1
Ques. 1JEE Main 2024, 27 January (Morning Shift)

A rectangular loop of length 2.5 m and width 2 m is placed at 60 to a magnetic field of 4 T. The loop is removed from the field in 10 sec. The average emf induced in the loop during this time is

  1. -2 V
  2. +2 V
  3. +1 V
  4. -1 V

Answer

(3) +1 V

Solution

avg=- t, =BA

60 is the angle between B and the area vector of the loop

i=4 (2.5 2) 60 =10 Wb, f=0

avg=- 0-1010=+1 V

Answer: (3)

Keep practising — Electromagnetic Induction

Ques. 2JEE Main 2024, 27 January (Morning Shift)

Two coils have mutual inductance 0.002 H. The current changes in the first coil according to the relation i = i0 , where i0 = 5 A and = 50 rad/s. The maximum value of emf in the second coil is V. The value of is .

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