Two coils have mutual inductance 0.002 H. The current changes in the first coil according to the relation i = i0 , where i0 = 5 A and = 50 rad/s. The maximum value of emf in the second coil is V. The value of is .
Answer
2
Solution
e = -M didt = -Mi0 t
emax = Mi0 = 0.002 5 50
= 0.5 = 2 V
= 2
Answer: 2