Wavenumber for a radiation having 5800 Å wavelength is x 10 cm-1. The value of x is . (Integer answer)
Answer
1724
Solution
= 1 with λ = 5800 Å = 5800 10-8 cm
= 15800 10-8 = 17241 cm-1
= 1724.1 10 cm-1, so x = 1724.
Answer: 1724
Wavenumber for a radiation having 5800 Å wavelength is x 10 cm-1. The value of x is . (Integer answer)
1724
= 1 with λ = 5800 Å = 5800 10-8 cm
= 15800 10-8 = 17241 cm-1
= 1724.1 10 cm-1, so x = 1724.
Answer: 1724
Frequency of the de-Broglie wave of electron in Bohr's first orbit of hydrogen atom is 1013 Hz (nearest integer). [Given : RH (Rydberg constant) = 2.18 10-18 J, h (Planck's constant) = 6.6 10-34 J. s.]
For hydrogen atom, energy of an electron in first excited state is -3.4 eV. K.E. of the same electron of hydrogen atom is x eV. Value of x is 10-1 eV. (Nearest integer)
The value of Rydberg constant (RH) is 2.18 10-18 J. The velocity of electron having mass 9.1 10-31 kg in Bohr's first orbit of hydrogen atom = 105 ms-1 (nearest integer).
In an atom, total number of electrons having quantum numbers n = 4, |ml| = 1 and ms = - 12 is .
The de-Broglie's wavelength of an electron in the 4th orbit is 0. (a0 = Bohr's radius)
The maximum number of orbitals which can be identified with n = 4 and ml = 0 is .
According to the wave-particle duality of matter by de-Broglie, which of the following graph plot presents most appropriate relationship between wavelength of electron ( ) and momentum of electron (p)?
The number of radial node/s for 3p orbital is :
The ionization energy of sodium in kJ mol-1, if electromagnetic radiation of wavelength 242 nm is just sufficient to ionize sodium atom is .
The four quantum numbers for the electron in the outermost orbital of potassium (atomic no. 19) are