A metal target with atomic number Z = 46 is bombarded with a high energy electron beam. The emission of X-rays from the target is analyzed. The ratio r of the wavelengths of the K -line and the cut-off is found to be r = 2. If the same electron beam bombards another metal target with Z = 41, the value of r will be
- 2.53
- 1.27
- 2.24
- 1.58
Answer
(1) 2.53
Solution
Cut-off wavelength = hceV depends only on the accelerating voltage — same for both targets.
Moseley's law: 1 K (Z-1)2 K (41) K (46) = ( 4540 )2 = 1.2656
r' = 2 1.2656 = 2.53
Answer: (A)