Rods x and y of equal dimensions but of different materials are joined as shown in figure. Temperatures of end points A and F are maintained at 100 and 40 respectively. Given the thermal conductivity of rod x is three times of that of rod y, the temperatures at junction points B and E are (close to): [figure]
- 60 and 45 respectively
- 80 and 70 respectively
- 89 and 73 respectively
- 80 and 60 respectively
Answer
(3) 89 and 73 respectively
Solution
Thermal resistance Rth = lkA; equal dimensions and kx = 3ky
if Rx = r, then Ry = 3r
Path B–C–E (two y rods): 3r + 3r = 6r
Path B–D–E (two x rods): r + r = 2r
These are in parallel: RBE = 6r 2r6r + 2r = 1.5r
Total: RAF = RAB + RBE + REF = r + 1.5r + 3r = 5.5r
Heat current: H = 100 - 405.5r = 605.5r
TB = 100 - H r = 100 - 605.5 100 - 10.9 = 89.1
TE = 40 + H 3r = 40 + 1805.5 40 + 32.7 = 72.7
TB 89 and TE 73
Answer: (3)