A screw gauge has least count of 0.01 mm and there are 50 divisions in its circular scale. The pitch of the screw gauge is :
- 0.25 mm
- 0.5 mm
- 1.0 mm
- 0.01 mm
Answer
(2) 0.5 mm
Solution
Least count = PitchNumber of divisions on circular scale
⇒ Pitch = Least count Number of divisions
= 0.01 50
= 0.5 mm
Answer: (2)