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Differential Equations · Question 23

JEE Main 2026 (Online) 21st January Morning ShiftMCQEasy📈 Topic in 71% papers+4−1
1

Let y = y(x) be the solution curve of the differential equation (1 + x2)dy + (y - -1 x)dx = 0, y(0) = 1. Then the value of y(1) is :

  1. 4e /4 - 2 - 1
  2. 2e /4 + 4 - 1
  3. 4e /4 + 2 - 1
  4. 2e /4 - 4 - 1

Answer

(2) 2e /4 + 4 - 1

Solution

dydx + y1 + x2 = -1 x1 + x2 (linear)

I.F. = e dx1 + x2 = e -1 x

y e -1 x = -1 x1 + x2e -1 xdx

Put -1 x = t: t et dt = (t - 1)et + C

y = -1 x - 1 + C e- -1 x

y(0) = 1 1 = 0 - 1 + C C = 2

y(1) = 4 - 1 + 2e- /4 = 2e /4 + 4 - 1

Answer: (2)

JEE Main 2026 (Online) 21st January Morning Shift

Keep practising — Differential Equations

2

Let y = y(x) be the solution of the differential equation x dydx - 2y = 2 + 3 x, x (- 2, 2 ), y(0) = - 74. Then y ( 6 ) is equal to :

  1. - 52
  2. -3 2 - 7
  3. - 54
  4. -3 3 - 7
JEE Main 2026 (Online) 21st January Evening Shift
3

Let f(x) = x - 1 and g(x) = ex for x R. If dydx = (e-2 x g(f(f(x))) - y x ), y(0) = 0, then y(1) is

  1. 1-e3e4
  2. e-1e4
  3. 1-e2e4
  4. 2e-1e3
JEE Main 2025 (Online) 8th April Evening Shift
4

Let y = y(x) be the solution curve of the differential equation x (x2 + ex )dy + (ex(x - 2)y - x3 )dx = 0, x > 0, passing through the point (1, 0). Then y(2) is equal to :

  1. 22 + e2
  2. 44 - e2
  3. 44 + e2
  4. 22 - e2
JEE Main 2025 (Online) 7th April Morning Shift
5

Let y = y(x) be the solution of the differential equation (x2 + 1)y' - 2xy = (x4 + 2x2 + 1) x, y(0) = 1. Then -33 y(x) dx is :

  1. 36
  2. 24
  3. 18
  4. 30
JEE Main 2025 (Online) 7th April Evening Shift
6

Let f : [0, ) R be a differentiable function such that f(x) = 1 - 2x + 0x ex-t f(t) dt for all x [0, ). Then the area of the region bounded by y = f(x) and the coordinate axes is

  1. 5
  2. 2
  3. 2
  4. 12
JEE Main 2025 (Online) 4th April Morning Shift
7

If a curve y = y(x) passes through the point (1, 2 ) and satisfies the differential equation (7x4 y - ex cosec y ) dxdy = x5, x 1, then at x = 2, the value of y is :

  1. 2e2 + e64
  2. 2e2 - e64
  3. 2e2 - e128
  4. 2e2 + e128
JEE Main 2025 (Online) 4th April Evening Shift
8

Let g be a differentiable function such that 0x g(t) dt = x - 0x t g(t) dt, x 0 and let y = y(x) satisfy the differential equation dydx - y x = 2(x+1) x g(x), x [0, 2 ). If y(0) = 0, then y ( 3 ) is equal to

  1. 4 3
  2. 2 3
  3. 2 3 3
  4. 4 3 3
JEE Main 2025 (Online) 3rd April Morning Shift
9

Let y = y(x) be the solution of the differential equation dydx + 3( 2 x)y + 3y = 2 x, y(0) = 13 + e3. Then y ( 4 ) is equal to :

  1. 43
  2. 23 + e3
  3. 43 + e3
  4. 23
JEE Main 2025 (Online) 3rd April Evening Shift
10

Let f : R R be a thrice differentiable odd function satisfying f'(x) 0, f''(x) = f(x), f(0) = 0, f'(0) = 3. Then 9f( e 3) is equal to .

JEE Main 2025 (Online) 2nd April Morning Shift
11

Let f : [1, ) [2, ) be a differentiable function. If 10 1x f(t) dt = 5xf(x) - x5 - 9 for all x 1, then the value of f(3) is :

  1. 22
  2. 26
  3. 32
  4. 18
JEE Main 2025 (Online) 2nd April Evening Shift

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