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Integrals · Question 26

JEE Main 2026 (Online) 23rd January Evening ShiftNumericalMedium📈 Topic in 16% papers+4
1

The number of elements in the set S = \x : x [0, 100] and 0x t2 (x - t) dt = x2 \ is

Answer

16

Solution

Put x - t = u: 0x t2 (x - t) dt = 0x (x - u)2 u du

By parts: = [-(x - u)2 u ]0x - 0x 2(x - u) u du

= x2 - 2 0x (x - u) u du

0x (x - u) u du = [(x - u) u ]0x + 0x u du = 1 - x

0x t2 (x - t) dt = x2 - 2 + 2 x

Given equation: x2 - 2 + 2 x = x2 x = 1

x = 2n , and 0 2n 100 0 n 1002 15.9

n = 0, 1, 2, , 15

Number of elements = 16

Answer: 16

JEE Main 2026 (Online) 23rd January Evening Shift

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10

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11

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