Two positive ions, each carrying a charge q, are separated by a distance d. If F is the force of repulsion between the ions, the number of electrons missing from each ion will be (e being the charge on an electron)
- 4 0 F d2e2
- 4 0 F e2d2
- 4 0 F d2e2
- 4 0 F d2q2
Answer
(3) 4 0 F d2e2
Solution
By Coulomb's law, F = 14 0 q2d2
q2 = 4 0 F d2
q = 4 0 F d2
Charge is quantised, q = ne
n = qe = 4 0 F d2e2
Answer: (3)