Two identical conducting spheres P and S with charge Q on each, repel each other with a force 16 N. A third identical uncharged conducting sphere R is successively brought in contact with the two spheres. The new force of repulsion between P and S is :
- 1 N
- 6 N
- 12 N
- 4 N
Answer
(2) 6 N
Solution
identical spheres in contact share the total charge equally:
R touches P: qP = qR = Q + 02 = Q2
R touches S: qS = qR = Q2 + Q2 = 3Q4
F qP qS F'F = Q2 3Q4Q Q = 38
F' = 38 16 = 6 N
Answer: (2)