The binding energy per nucleon of 20983Bi is MeV. [Take m( 20983Bi) = 208.980388 u, mp = 1.007825 u, mn = 1.008665 u, 1 u = 931 MeV/c2]
- 7.48
- 7.84
- 8.79
- 6.94
Answer
(2) 7.84
Solution
Z = 83, N = A - Z = 209 - 83 = 126
Zmp = 83 1.007825 = 83.649475 u
Nmn = 126 1.008665 = 127.091790 u
Mass defect: m = 83.649475 + 127.091790 - 208.980388 = 1.760877 u
BE = 1.760877 931 = 1639.4 MeV
BEA = 1639.4209 = 7.84 MeV
Answer: (2)