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Chemical Kinetics

JEE Main 2024 (Online) 29th January Morning ShiftNumericalEasy📈 Topic in 22% papers+4
Ques. 1JEE Main 2024, 29 January (Morning Shift)

For a reaction taking place in three steps at same temperature, overall rate constant K = K1 K2K3. If Ea1, Ea2 and Ea3 are 40, 50 and 60 kJ/mol respectively, the overall Ea is kJ/mol.

Answer

30

Solution

Arrhenius: K = A e-Ea/RT for each step

K = K1 K2K3 = A1 A2A3 e-(Ea1 + Ea2 - Ea3)/RT

⇒ Ea = Ea1 + Ea2 - Ea3 = 40 + 50 - 60 = 30 kJ/mol

Answer: 30

Keep practising — Chemical Kinetics

Ques. 2JEE Main 2024, 29 January (Evening Shift)

The half-life of radioisotope bromine - 82 is 36 hours. The fraction which remains after one day is 10-2. (Given antilog 0.2006 = 1.587)

Ques. 3JEE Main 2024, 27 January (Morning Shift)

Consider the following data for the given reaction 2HI(g) H2(g) + I2(g) [figure] The order of the reaction is .

Ques. 4JEE Main 2024, 27 January (Evening Shift)

Time required for completion of 99.9% of a First order reaction is times of half life (t1/2) of the reaction.

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