At t=0, a body of mass 100 g starts moving under the influence of a force (5 i+10 j ) N. After 2 s its position is (2x i+5y j ) m. The ratio x:y is .
- 1 : 2
- 2 : 5
- 5 : 2
- 5 : 4
Answer
(4) 5 : 4
Solution
m=100 g=0.1 kg
a= Fm= 5 i+10 j0.1= (50 i+100 j ) m s-2
The body starts from rest at the origin:
r= 12 at2= 12 (50 i+100 j )(2)2
r= (100 i+200 j ) m
Comparing with (2x i+5y j ) m:
2x=100 x=50; 5y=200 y=40
x:y=50:40=5:4
Answer: (4)