The resistance R= VI where V=(200 5) V and I=(20 0.2) A, the percentage error in the measurement of R is :
- 5.5%
- 3%
- 7%
- 3.5%
Answer
(4) 3.5%
Solution
R= VI RR= VV+ II
in a quotient the relative errors add.
RR 100= ( 5200+ 0.220 ) 100
=2.5\%+1\%=3.5\%
Answer: (4)