If mass is written as m=kcPG-1/2h1/2 then the value of P will be : (Constants have their usual meaning with k a dimensionless constant)
- 1/3
- -1/3
- 1/2
- 2
Answer
(3) 1/2
Solution
[c]= LT-1, [G]= M-1L3T-2, [h]= ML2T-1
M1L0T0=[ LT-1]P[ M-1L3T-2]-1/2[ ML2T-1]1/2
Powers of L: P- 32+1=0
P= 12 (T: -P+1- 12=0 ✓)
Answer: (3)