The solubility of BaSO4 in water is 2.42 10-3 g L-1 at 298 K. The value of its solubility product (Ksp) will be (Given molar mass of BaSO4 = 233 g mol-1)
- 1.08 10-10 mol2 L-2
- 1.08 10-12 mol2 L-2
- 1.08 10-14 mol2 L-2
- 1.08 10-8 mol2 L-2
Answer
(1) 1.08 10-10 mol2 L-2
Solution
Molar solubility s = 2.42 10-3233
= 1.04 10-5 mol L-1
BaSO4(s) Ba2+(aq) + SO42-(aq) ⇒ Ksp = s2
⇒ Ksp = (1.04 10-5)2
= 1.08 10-10 mol2 L-2
Answer: (1)