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Relations and Functions · Question 1

JEE Main 2026 (Online) 8th April Evening ShiftNumericalMedium📈 Topic in 6% papers+4
1

The sum of squares of all the real solutions of the equation (x+1) (2x2+5x+3 )=4- (2x+3) (x2+2x+1 ) is equal to .

Answer

2

Solution

Conditions: x+1>0, x+1 1, 2x+3>0, 2x+3 1 x>-1, x 0

2x2+5x+3=(2x+3)(x+1), x2+2x+1=(x+1)2

Let t= (x+1)(2x+3) (t 0)

LHS =1+t; RHS =4-2 (2x+3)(x+1)=4- 2t

1+t=4- 2t t2-3t+2=0 t=1 or 2

t=1: 2x+3=x+1 x=-2 (rejected, x>-1)

t=2: 2x+3=(x+1)2 x2=2 x= 2 (x=- 2<-1 rejected)

sum of squares of real solutions = ( 2 )2=2

Answer: 2

JEE Main 2026 (Online) 8th April Evening Shift

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2

Let [ ] denote the greatest integer function. If the domain of the function f(x)= -1 ( x+[x]3 ) is [ , ), then 2+ 2 is equal to :

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3

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7

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8

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9

Let f(x) = [x]2 - [x + 3] - 3, x R, where [.] is the greatest integer function. Then

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Let the domain of the function f(x) = 3 5 (7 - 2 (x2 - 10x + 85 ) ) + -1 ( | 3x - 717 - x | ) be ( , ]. Then + is equal to :

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11

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