If E and G respectively denote energy and gravitational constant, then EG has the dimensions of :
- [M2] [L-2] [T-1]
- [M2] [L-1] [T0]
- [M] [L-1] [T-1]
- [M] [L0] [T0]
Answer
(2) [M2] [L-1] [T0]
Solution
[E] = [ML2T-2]
∵ F = Gm1m2r2 ⇒ G = Fr2m1m2
⇒ [G] = [MLT-2][L2][M2] = [M-1L3T-2]
∴ [ EG ] = [ML2T-2] [M-1L3T-2] = [M2] [L-1] [T0]
Answer: (2)