In the given figure an ammeter A consists of a 240 coil connected in parallel to a 10 shunt. The reading of the ammeter is mA. [figure]
Answer
160
Solution
Ammeter resistance (coil ∥ shunt): RA = 240 10240 + 10 = 9.6
Total resistance = 140.4 + 9.6 = 150
the ammeter reads the whole circuit current
I = 24150 = 0.16 A = 160 mA
Answer: 160