Which complex compound will give four isomers?
- [Fe(en)3]Cl3
- [Co(en)(NH3)2Cl2]Cl
- [Fe(PPh3)3NH3ClBr]Cl
- [Co(PPh3)3Cl]Cl3
Answer
(2) [Co(en)(NH3)2Cl2]Cl
Solution
[Co(en)(NH3)2Cl2]+ is an octahedral complex of the type [M(AA)a2b2].
Geometrical isomers:
(i) the two Cl trans to each other (two NH3 cis) — has a plane of symmetry, optically inactive;
(ii) the two NH3 trans to each other (two Cl cis) — optically inactive;
(iii) both Cl cis and both NH3 cis — no plane of symmetry, exists as a d and l pair.
Total isomers = 1 + 1 + 2 = 4
[Fe(en)3]3+ gives only 2 (d and l) and [Fe(PPh3)3NH3ClBr]+ (type Ma3bcd) gives 5 stereoisomers.
Answer: (2)