Ques. 1JEE Main 2024, 27 January (Morning Shift)
n-1Cr= (k2-8 )nCr+1 if and only if :
- 2 2<k<2 3
- 2 2<k 3
- 2 3<k<3 3
- 2 3<k 3 2
Answer
(2) 2 2<k 3
Solution
nCr+1= nr+1 n-1Cr k2-8= n-1CrnCr+1= r+1n
0 r n-1 0< r+1n 1
8<k2 9 2 2<|k| 3
k [-3,-2 2) (2 2,3]
Of the options, only 2 2<k 3 fits.
Answer: (2)