In an ammeter, 5\% of the main current passes through the galvanometer. If resistance of the galvanometer is G, the resistance of ammeter will be :
- G200
- G199
- 199 G
- 200 G
Answer
BONUS
Solution
Shunt S in parallel with G: IgG=(I-Ig)S
0.05I =0.95I S= G19
G and S are in parallel: RA= GSG+S= G G19G+ G19= G20
G20 is not among the options, no option is correct question dropped
Answer: Bonus (full marks to all who attempted)