Two circular coils P and Q of 100 turns each have same radius of cm. The currents in P and Q are 1 A and 2 A respectively. P and Q are placed with their planes mutually perpendicular with their centers coincide. The resultant magnetic field induction at the center of the coils is x mT, where x= . [Use 0=4 10-7 TmA-1]
Answer
20
Solution
Field at the centre of a coil: B= 0NI2r, with r= 10-2 m
BP= 4 10-7 100 12 10-2=2 10-3 T =2 mT
BQ=2BP=4 mT
planes perpendicular BP BQ
B= 22+42= 20 mT
x=20
Answer: 20