Solutions

JEE Main 2025 (Online) 23rd January Evening ShiftMCQHard📈 Topic in 16% papers+4−1

Ques. 1JEE Main 2025, 23 January (Evening Shift)

Consider a binary solution of two volatile liquid components 1 and 2. x1 and y1 are the mole fractions of component 1 in liquid and vapour phase, respectively. The slope and intercept of the linear plot of 1x1 vs 1y1 are given respectively as :

P10P20, P10-P20P20
P20P10, P20-P10P10
P20P10, P10-P20P20
P10P20, P20-P10P20

Answer

(4) P10P20, P20-P10P20

Solution

p1=x1p10=y1pT, pT=p20+x1(p10-p20)

⇒ 1y1= p20p10 1x1+ p10-p20p10

Make 1x1 the subject: 1x1= p10p20 1y1+ p20-p10p20

∴ slope = p10p20, intercept = p20-p10p20

Answer: (4)

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Ques. 2JEE Main 2025, 22 January (Morning Shift)

Arrange the following solutions in order of their increasing boiling points. (i) 10-4 M NaCl (ii) 10-4 M Urea (iii) 10-3 M NaCl (iv) 10-2 M NaCl

(i) < (ii) < (iii) < (iv)
(ii) < (i) < (iii) < (iv)
(iv) < (iii) < (i) < (ii)
(ii) < (i) (iii) < (iv)

Ques. 3JEE Main 2025, 22 January (Evening Shift)

Density of 3 M NaCl solution is 1.25 g/mL. The molality of the solution is :

2.79 m
2 m
1.79 m
3 m

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