PYQSidePowered by
ExamsMy practice
If the equation a(b-c)x2+b(c-a)x+c(a-b)=0 has equal roots, where a+c=15 and b= 365, then a2+c2 is equal to .
117
Sum of coefficients =0 x=1 is a root; the roots are equal, so both are 1.
Product of roots = c(a-b)a(b-c)=1 2ac=b(a+c)= 365 15=108 ac=54
a2+c2=(a+c)2-2ac=225-108=117
Answer: 117
The number of complex numbers z, satisfying |z|=1 and | z z+ zz |=1, is :
Let , be the roots of the equation x2-ax-b=0 with Im( )<Im( ). Let Pn= n- n. If P3=-5 7 i, P4=-3 7 i, P5=11 7 i and P6=45 7 i, then | 4+ 4 | is equal to .
Let z1,z2 and z3 be three complex numbers on the circle |z|=1 with (z1)= - 4, (z2)=0 and (z3)= 4. If |z1 z2+z2 z3+z3 z1 |2= + 2, , Z, then the value of 2+ 2 is :
Let and be the distinct roots of 2x2+( )x-1=0, (0,2 ). If m and M are the minimum and the maximum values of 4+ 4, then 16(M+m) equals :
Let the curve z(1+i)+ z(1-i)=4, z , divide the region |z-3| 1 into two parts of areas and . Then | - | equals :