The shortest distance between the lines x - 32 = y + 15-7 = z - 95 and x + 12 = y - 11 = z - 9-3 is
- 8 3
- 6 3
- 5 3
- 4 3
Answer
(4) 4 3
Solution
S.D. = |( a2 - a1) ( b1 b2)|| b1 b2|
a2 - a1 = (-1, 1, 9) - (3, -15, 9) = (-4, 16, 0)
b1 b2 = vmatrix i & j & k \ 2 & -7 & 5 \ 2 & 1 & -3 vmatrix = 16 i + 16 j + 16 k
| b1 b2| = 16 3, dot product = -64 + 256 + 0 = 192
S.D. = 19216 3 = 12 3 = 4 3
Answer: (4)