The work function of a surface of a photosensitive material is 6.2 eV. The wavelength of the incident radiation for which the stopping potential is 5 V lies in the
- infrared region
- X-ray region
- Ultraviolet region
- Visible region
Answer
(3) Ultraviolet region
Solution
Einstein's photoelectric equation: h = 0 + eV0
h = 6.2 + 5 = 11.2 eV
= hcE = 1240 eV nm11.2 eV 111 nm
This lies in the ultraviolet region.
Answer: (3)