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Motion in a Straight Line · Question 42

AIPMT 2003MCQMedium📈 Topic in 38% papers+4−1
1

A man throws balls with the same speed vertically upwards one after the other at an interval of 2 seconds. What should be the speed of the throw so that more than two balls are in the sky at any time ? (Given g = 9.8 m/s2)

  1. more than 19.6 m/s
  2. at least 9.8 m/s
  3. any speed less than 19.6 m/s
  4. only with speed 19.6 m/s.

Answer

(1) more than 19.6 m/s

Solution

Balls are thrown every 2 s. For more than two balls to be in the air at any time, each ball must stay in the air for more than 2 2 = 4 s.

Time of flight: T = 2ug

⇒ 2ug > 4

⇒ u > 2g

= 2 9.8

= 19.6 m/s

∴ The speed of throw must be more than 19.6 m/s.

Answer: (1)

AIPMT 2003

Keep practising — Motion in a Straight Line

2

If a ball is thrown vertically upwards with speed u, the distance covered during the last t seconds of its ascent is

  1. ut
  2. 12gt2
  3. ut - 12gt2
  4. (u + gt)t.
AIPMT 2003
3

A particle is thrown vertically upward. Its velocity at half of the height is 10 m/s, then the maximum height attained by it is (g = 10 m/s2)

  1. 8 m
  2. 20 m
  3. 10 m
  4. 16 m
AIPMT 2001
4

Motion of a particle is given by equation s = (3t3 + 7t2 + 14t + 8) m. The value of acceleration of the particle at t = 1 s is

  1. 10 m/s2
  2. 32 m/s2
  3. 23 m/s2
  4. 16 m/s2
AIPMT 2000

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