Average force exerted on a non-reflecting surface at normal incidence is 2.4 10-4 N. If 360 W/cm2 is the light energy flux during span of 1 hour 30 minutes, then the area of the surface is:
- 20 m2
- 0.2 m2
- 0.1 m2
- 0.02 m2
Answer
(4) 0.02 m2
Solution
Non-reflecting (perfect absorber) at normal incidence: F = IAc
I = 360 W/cm2 = 360 104 W/m2
A = FcI = 2.4 10-4 3 1083.6 106
= 2 10-2 m2 = 0.02 m2
force and flux are both rates, the time (1 h 30 min) is not needed.
Answer: (4)