The magnetic field in a plane electromagnetic wave is By = (3.5 10-7 ) (1.5 103 x + 0.5 1011 t ) T. The corresponding electric field will be :
- Ez = 105 (1.5 103 x + 0.5 1011 t ) V m-1
- Ey = 10.5 (1.5 103 x + 0.5 1011 t ) V m-1
- Ey = 1.17 (1.5 103 x + 0.5 1011 t ) V m-1
- Ez = 1.17 (1.5 103 x + 0.5 1011 t ) V m-1
Answer
(1) Ez = 105 (1.5 103 x + 0.5 1011 t ) V m-1
Solution
Amplitude: E0 = cB0 = 3 108 3.5 10-7 = 105 V m-1
Direction: the phase (kx + t) shows the wave moves along -x. Since E B and both are perpendicular to the direction of travel, E is along z ( k j = - i, so E B points along -x).
Ez = 105 (1.5 103 x + 0.5 1011 t ) V m-1
Answer: (1)