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Alcohols, Phenols and Ethers

JEE Main 2024 (Online) 27th January Evening ShiftMatchingEasy📈 Topic in 22% papers+4−1
Ques. 1JEE Main 2024, 27 January (Evening Shift)

Match List - I with List - II. Choose the correct answer from the options given below :

  1. (A)-(II), (B)-(I), (C)-(III), (D)-(IV)
  2. (A)-(IV), (B)-(I), (C)-(III), (D)-(II)
  3. (A)-(IV), (B)-(III), (C)-(I), (D)-(II)
  4. (A)-(II), (B)-(III), (C)-(I), (D)-(IV)

Answer

(3) (A)-(IV), (B)-(III), (C)-(I), (D)-(II)

Solution

(A): –COOH enters ortho ⇒ Kolbe's reaction: (i) NaOH, (ii) CO2, (iii) HCl ⇒ (A) is (IV)

(B): –CHO enters ortho ⇒ Reimer–Tiemann reaction: (i) NaOH, CHCl3, (ii) NaOH, (iii) HCl ⇒ (B) is (III)

(C): phenol is oxidised to p-benzoquinone by Na2Cr2O7, H2SO4 ⇒ (C) is (I)

(D): Williamson synthesis: C6H5O-Na+ + CH3Cl C6H5OCH3 + NaCl ⇒ (D) is (II)

∴ (A)-(IV), (B)-(III), (C)-(I), (D)-(II)

Answer: (3)

Keep practising — Alcohols, Phenols and Ethers

Ques. 2JEE Main 2024, 27 January (Evening Shift)

The final product A, formed in the following reaction sequence is: [figure]

  1. [figure]
  2. [figure]
  3. Ph-CH2-CH2-CH2-OH
  4. Ph-CH2-CH2-CH3

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