The kinetic energies of a planet in an elliptical orbit about the Sun, at positions A, B and C are KA, KB and KC, respectively. AC is the major axis and SB is perpendicular to AC at the position of the Sun S as shown in the figure. Then [figure]
- KA < KB < KC
- KA > KB > KC
- KB < KA < KC
- KB > KA > KC
Answer
(2) KA > KB > KC
Solution
The gravitational force on the planet is central ⇒ angular momentum about S is conserved (Kepler's second law).
From the figure, distance from the Sun: rA < rB < rC (A is the perihelion, C is the aphelion).
∵ The planet moves fastest when nearest to the Sun and slowest when farthest
⇒ vA > vB > vC
∴ K = 12mv2 ⇒ KA > KB > KC
Answer: (2)