The 'Spin only' Magnetic moment for [Ni(NH3)6]2+ is 10-1 BM. (given = Atomic number of Ni : 28)
Answer
28
Solution
Ni (Z = 28): [Ar]3d84s2 ⇒ Ni2+: 3d8; octahedral field ⇒ t2g6eg2
[figure]
∵ With 8 d-electrons, eg always holds 2 unpaired electrons (whatever the field strength of NH3)
= n(n+2) = 8 = 2.83 BM = 28.3 10-1 BM ≈ 28 10-1 BM
Answer: 28