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Mechanical Properties of Fluids · Question 27

AIPMT 2014MCQMedium📈 Topic in 38% papers+4−1
1

A certain number of spherical drops of a liquid of radius r coalesce to form a single drop of radius R and volume V. If T is the surface tension of the liquid, then

  1. energy = 4VT ( 1r - 1R ) is released.
  2. energy = 3VT ( 1r + 1R ) is absorbed.
  3. energy = 3VT ( 1r - 1R ) is released.
  4. energy is neither released nor absorbed.

Answer

(3) energy = 3VT ( 1r - 1R ) is released.

Solution

Number of drops: n = V 43 r3

Initial surface area = n 4 r2 = 3Vr; final area = 4 R2 = 3VR

Decrease in area = 3V ( 1r - 1R ) (positive, since r < R)

Energy released = 3VT ( 1r - 1R )

Answer: (3)

AIPMT 2014

Keep practising — Mechanical Properties of Fluids

2

The wettability of a surface by a liquid depends primarily on

  1. density
  2. angle of contact between the surface and the liquid
  3. viscosity
  4. surface tension
NEET 2013
3

A fluid is in streamline flow across a horizontal pipe of variable area of cross section. For this which of the following statements is correct?

  1. The velocity is maximum at the narrowest part of the pipe and pressure is maximum at the widest part of the pipe.
  2. Velocity and pressure both are maximum at the narrowest part of the pipe.
  3. Velocity and pressure both are maximum at the widest part of the pipe.
  4. The velocity is minimum at the narrowest part of the pipe and the pressure is minimum at the widest part of the pipe.
NEET 2013 (Karnataka)

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