A concave mirror of focal length 10 cm forms an image which is double the size of object when the object is placed at two different positions. The distance between the two positions of the object is cm.
Answer
10
Solution
For a mirror m=- vu= ff-u; concave mirror ⇒ f=-10 cm
Real, inverted image (m=-2): -10-10-u=-2 ⇒ -10=20+2u ⇒ u=-15 cm
Virtual, erect image (m=+2): -10-10-u=2 ⇒ -10=-20-2u ⇒ u=-5 cm
∴ Distance between the two positions =15-5=10 cm
Answer: 10