An object AB is placed 15 cm on the left of a convex lens P of focal length 10 cm. Another convex lens Q is now placed 15 cm right of lens P. If the focal length of lens Q is 15 cm, the final image is .
- virtual, formed at 7.5 cm right of lens Q, with a size bigger than that of AB
- real, formed at 7.5 cm right of lens Q, with a size same as that of AB
- formed at infinity.
- real, formed at 7 cm right of lens Q, with a size smaller than that of AB
Answer
(2) real, formed at 7.5 cm right of lens Q, with a size same as that of AB
Solution
[figure]
Lens P (f1=+10 cm, u1=-15 cm):
1v1- 1u1= 1f1 1v1= 110- 115= 130
v1=+30 cm, m1= v1u1= 30-15=-2
I1 is 30 cm right of P, i.e. 15 cm right of Q virtual object for Q: u2=+15 cm
Lens Q (f2=+15 cm): 1v2= 1f2+ 1u2= 115+ 115= 215
v2=+7.5 cm (real, right of Q), m2= 7.515= 12
m=m1m2=(-2) 12=-1 inverted, same size as AB
Real image, 7.5 cm right of Q, same size as AB
Answer: (2)