A soap bubble is blown to a diameter of 7 cm. 36960 erg of work is done in blowing it further. If surface tension of soap solution is 40 dyne/cm then the new radius is cm. Take ( = 227 ).
Answer
7
Solution
Work = surface tension increase in area; a bubble has 2 surfaces.
W=T 2 4 (R2-r2), r=3.5 cm
36960=40 8 227(R2-12.25)
R2-12.25= 36960 77040=36.75
R2=49
R=7 cm
Answer: 7