Two slabs with square cross section of different materials (1, 2) with equal sides (l) and thickness d1 and d2 such that d2 = 2d1 and l > d2. Considering lower edges of these slabs are fixed to the floor, we apply equal shearing force on the narrow faces. The angle of deformation is 2 = 2 1. If the shear modulus of material 1 is 4 109 N/m2, then shear modulus of material 2 is x 109 N/m2, where value of x is .
Answer
1
Solution
The shearing force F acts tangentially on a narrow face of area A = l d.
Shear modulus: = F/A = Fl d 1d (F and l same)
2 1 = d1 1d2 2 = d1 1(2d1)(2 1) = 14
2 = 4 1094 = 1 109 N/m2
x = 1
Answer: 1