Let the circle C1 : x2 + y2 - 2(x + y) + 1 = 0 and C2 be a circle having centre at (-1, 0) and radius 2. If the line of the common chord of C1 and C2 intersects the y-axis at the point P, then the square of the distance of P from the centre of C1 is:
- 4
- 6
- 2
- 1
Answer
(3) 2
Solution
S1: x2 + y2 - 2x - 2y + 1 = 0, centre (1, 1)
S2: (x + 1)2 + y2 = 4 x2 + y2 + 2x - 3 = 0
Common chord: S1 - S2 = 0 -4x - 2y + 4 = 0 2x + y = 2
P is on the y-axis, put x = 0 P(0, 2)
(distance)2 = (0 - 1)2 + (2 - 1)2 = 2
Answer: (3)